Reverse an Order Of a String Using JAVA

Reverse an Order Of a String Using JAVA

In this post i am going to show you how to reverse the order of the given string. the order of the string will be reverse means the last whole word become the first and first become the last word of the string and other remaining word also change the position in the order they appear.

Example: jiten vaghela

ouput: vaghela jiten

Download Program: Click here

Program:

import java.util.*;

public class reverseOrder{

public static void main(String [] args){

Scanner input=new Scanner(System.in);

System.out.print("Enter your String:");

String data=input.nextLine();

String [] arrayData=data.split(" ");

data=new String("");

for(int i=arrayData.length-1;i>=0;i--){

data+=arrayData[i]+" ";

}

System.out.println("Reverse String:"+data);

}

}

output:

Count Sub String Occurrence Algorithm With Example using JAVA

Count Sub String Occurrence Algorithm With Example using JAVA

Sub String Occurrence count means to check how many  times a particular  part of a string repeat in the given string.

Algorithm:

step 1: get the length of MainString and SubString variables and initialize i=j=count=0;

            ex:

            len1=mainString.length();

            len2=subString.length();

Step 2: start loop from i=0 to len1-len2;

            initialize the j with 0 and flag with true;

Step 3: check whether character of mainString at position i is equals to character of SubString at position j ?

             ex:

             if(mainString.charAt(i)==subString.charAt(j))

Step 4: if both are sem then start another loop with j=1 and j is j<=subString.length(); now check whether the character of mainString at position i+j is not Equals to character of SubString at position j. then make the flag = false and break the loop.

           ex:

           for(j=1;j<=SubString.length();j++){

                         if(mainString.charAt(i+j)!=subString(j)){

                                     flag=false;

                                       break;

                          }

            }

Step 5:out side the inner for loop check whether the flag value is true if yes then count= count+1

            ex:

            if(flag)

               count++;

Download Program: Click Here

Program:

import java.util.*;

public class reverse{

public static int getSubString(String mainString,String subString){

int max=1+mainString.length()-subString.length();

int count=0;

for(int i=0;i<max;i++){

boolean flag=true;

int j=0;

if(mainString.charAt(i)==subString.charAt(j)){

for(j=1;j<subString.length();j++){

if(mainString.charAt(i+j)!=subString.charAt(j)){

flag=false;

break;

}

}

}else

flag=false;

if(flag)

count++;

}

return count;

}

public static void main(String [] args){

Scanner input=new Scanner(System.in);

System.out.print("Enter Main String:");

String mainString=input.nextLine();

System.out.print("Enter Sub String :");

String subString=input.nextLine();

int count=getSubString(mainString,subString);

System.out.println("String Found:"+count);

}

}

compile the above code:javac subStringcounter.java

To Run the code: java subStringcounter

Output: